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| whizter
| Joined: 19 Jul 2007 | Posts: 30 | : | | Items |
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Posted: Thu Jul 26, 2007 7:26 pm Post subject: Coloring question |
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I don't understand why 4 colors are needed in this multicolor-examples from sudopedia, if I just fill the cells with 2 colors, I come to the same result:
sudopedia. org/wiki/Multi-Colors
Can someone explain?
EDIT: Ok, I think I understood it now. A Unit must only contain 2 of the candidates to form the chain. This means that 2 chains are required because there are no connections between them. Is this true? |
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| Ruud Site Admin
| Joined: 17 Sep 2005 | Posts: 708 | : | Location: Netherlands | Items |
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Posted: Thu Jul 26, 2007 8:33 pm Post subject: |
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In coloring, chains (or clusters, as I prefer to call them) can only be formed by conjugate pairs (2 candidates in a unit).
Multi-colors uses weak links between these chains. In techniques which depend on alternating inference, the pattern would be identified as a single chain.
Ruud |
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| whizter
| Joined: 19 Jul 2007 | Posts: 30 | : | | Items |
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Posted: Fri Jul 27, 2007 10:24 am Post subject: |
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Thanks for the reply. I've got another question:
I know that it is required to scan for X-Wing 2 times, row-based and column-based. Is this also required for Swordfish and Jellyfish or is there always a complementary one which in the end results in the same eliminations? I know that there is always a complementary one, but are there setups where a row-based searching wouldn't result in eliminations, but a column-based would? |
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| daj95376
| Joined: 05 Feb 2006 | Posts: 349 | : | | Items |
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Posted: Fri Jul 27, 2007 2:06 pm Post subject: |
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I believe there is always a complementary fish, but there's no guarantee that it's of the same size. A Swordfish may have a Jellyfish (or larger) as the complementary fish. |
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