Irregular boxes

rallveird · Posted: Wed Aug 10, 2005 3:51 pm Post subject: Irregular boxes

Well, it's me again. Just informing that I'm publishing irregular boxes on the sudokus now, in different sizes.

Take a look at:

http://www.menneske.no/sudoku/irr/3/eng/

You will find the other variants in the bottom of the leftbar.

Enjoy

Merri · Posted: Wed Aug 10, 2005 4:30 pm Post subject:

Taken down already? Gives 404.

rallveird · Posted: Wed Aug 10, 2005 5:34 pm Post subject:

Ah, sorry. Wrong link. I have corrected it now.

dukuso · Posted: Thu Aug 11, 2005 10:42 am Post subject:

waiting for (pan-) diagonal sudokus...

25*25 pandiagonal was suggested in the sudoku-player forum.
it could be an open problem whether these exist or not.

rallveird · Posted: Thu Aug 11, 2005 12:10 pm Post subject:

What do you mean by (pan-) diagonal? That the sudoku should have 1-25 in both diagonals too?

(I'm btw implementing the diagonal today and will probably publish some puzzles very soon.)

rallveird · Posted: Thu Aug 11, 2005 2:48 pm Post subject:

Here you got a regular (solution) 25x25 with the 2 diagonals also 1-25. Reduce it as you wish.

12 25 6 1 3 18 23 2 5 17 24 15 8 21 16 13 22 10 20 19 4 14 11 9 7
22 9 21 20 11 7 15 13 16 6 2 23 12 10 3 4 17 14 24 18 25 1 19 8 5
19 18 8 15 17 12 24 4 3 25 14 9 1 5 13 6 7 16 11 23 10 20 21 2 22
23 13 4 5 2 14 1 20 9 10 22 7 6 19 11 15 21 8 12 25 16 24 18 3 17
16 24 7 14 10 19 11 22 21 8 25 20 17 4 18 3 2 9 5 1 13 15 12 23 6
20 1 15 18 4 25 9 16 19 7 17 8 10 3 2 12 24 5 21 14 23 22 6 13 11
25 6 16 22 21 24 17 8 10 13 11 5 14 18 9 1 19 23 2 15 20 12 7 4 3
11 3 10 2 5 15 6 21 23 12 16 25 13 22 7 9 20 4 18 17 1 19 24 14 8
8 7 17 9 19 11 3 5 14 4 1 12 24 23 20 16 6 22 13 10 21 2 15 18 25
14 12 24 23 13 22 2 18 1 20 21 19 4 15 6 25 8 3 7 11 17 5 10 16 9
5 4 20 24 6 23 10 14 7 21 18 3 19 2 15 8 9 11 16 12 22 17 13 25 1
7 19 18 8 15 3 4 25 22 1 9 6 21 12 14 17 13 2 23 20 5 11 16 24 10
9 2 13 10 25 17 12 19 18 11 20 1 16 24 8 14 3 7 22 5 6 21 4 15 23
3 22 23 21 16 13 5 6 8 2 4 17 11 7 10 18 25 15 1 24 14 9 20 19 12
17 11 1 12 14 20 16 15 24 9 5 13 22 25 23 19 10 6 4 21 3 18 8 7 2
4 14 25 16 23 5 19 1 6 3 15 18 2 13 21 22 11 12 10 7 9 8 17 20 24
1 8 2 6 18 21 13 10 11 16 12 24 25 14 5 20 15 17 9 4 7 3 23 22 19
15 17 19 7 12 8 25 23 4 14 3 10 9 20 22 5 18 24 6 13 11 16 2 1 21
24 21 5 13 9 2 20 17 12 22 19 4 7 11 1 23 16 25 3 8 18 10 14 6 15
10 20 11 3 22 9 7 24 15 18 6 16 23 8 17 21 1 19 14 2 12 13 25 5 4
2 15 14 25 1 6 21 3 13 24 8 11 5 9 4 7 12 18 17 16 19 23 22 10 20
13 23 12 19 8 10 22 9 20 15 7 14 18 17 24 11 5 1 25 6 2 4 3 21 16
6 5 22 11 24 4 18 7 2 19 13 21 3 16 12 10 23 20 15 9 8 25 1 17 14
21 10 3 4 7 16 8 12 17 5 23 2 20 1 25 24 14 13 19 22 15 6 9 11 18
18 16 9 17 20 1 14 11 25 23 10 22 15 6 19 2 4 21 8 3 24 7 5 12 13

I presume you with pandiagonal mean that all the broken diagonals should be 1-25? I will try to make one now. Will keep you posted.

Btw, it seems 2x3 size (6 numbers) can't have both diagonal restriction and regular disjoint groups.

dukuso · Posted: Thu Aug 11, 2005 3:25 pm Post subject:

you can also require that the other , shorter diagonals
don't contain any symbol twice.
That's pretty hard to make such puzzles for even n !

Yes, pandiagonal means that you have 2*n broken diagonals
with n entries each. Also a difficult problem.
I don't think that you will find one without looking
it up, except the obvious linear ones.

And that is without the blocks matching too !
Interesting stuff.

rallveird · Posted: Thu Aug 11, 2005 3:58 pm Post subject:

Not sure I understand what you mean with shorter diagonals. Do you mean both the diagonals a number is a member of?

I've testet pandiagonal generation. It seems there are no 2x2 or 2x3 puzzles with this restriction.

dukuso · Posted: Thu Aug 11, 2005 4:05 pm Post subject:

rallveird · Posted: Thu Aug 11, 2005 4:19 pm Post subject:

25 isn't a prime. Does it mean that 25x25 isn't possible to make then?

1x5 and 1x7 was pretty easy to generate btw.

dukuso · Posted: Thu Aug 11, 2005 5:36 pm Post subject:

25 could be possible.

coprime to 6 : that means n mustn't be divisible by 2, nor 3

you can always make the "trivial" grids, cyclically shifting
the entries. But people will find out this earlier or later.